題目
難度：easy
Given two lists Aand B, and B is an anagram of A. B is an anagram of A means B is made by randomizing the order of the elements in A.
We want to find an index mapping P, from A to B. A mapping P[i] = j means the ith element in A appears in B at index j.
These lists A and B may contain duplicates. If there are multiple answers, output any of them.
For example, given
A = [12, 28, 46, 32, 50]
B = [50, 12, 32, 46, 28]
We should return
[1, 4, 3, 2, 0]
as P[0] = 1 because the 0th element of A appears at B[1], and P[1] = 4 because the 1st element of A appears at B[4], and so on.
Note:
A, B have equal lengths in range [1, 100].
A[i], B[i] are integers in range [0, 10^5].
第一次解法
/**
* @param {number[]} A
* @param {number[]} B
* @return {number[]}
*/
var anagramMappings = function(A, B) {
let res = []
A.forEach(function(item){
res.push(B.indexOf(item))
})
return res
};
# runtime : 94 ms
