<el-table
:data="tableData"
:span-method="arraySpanMethod"
border
style="width: 100%; margin-top: 20px">
<el-table-column
prop="id"
label="ID"
width="180">
</el-table-column>
<el-table-column
prop="name"
label="姓名">
</el-table-column>
<el-table-column
prop="amount1"
label="數值 1(元)">
</el-table-column>
<el-table-column
prop="amount2"
label="數值 2(元)">
</el-table-column>
<el-table-column
prop="amount3"
label="數值 3(元)">
</el-table-column>
</el-table>
export default {
data(){
return {
// 模擬后臺返回數據
tableData: [{
id: '12987122',
name: '王小虎',
amount1: '234',
amount2: '3.2',
amount3: 10
}, {
id: '12987123',
name: '王小虎',
amount1: '165',
amount2: '4.43',
amount3: 12
}, {
id: '12987124',
name: '王小虎',
amount1: '324',
amount2: '1.9',
amount3: 9
}, {
id: '12987125',
name: '王小虎',
amount1: '621',
amount2: '2.2',
amount3: 17
}, {
id: '12987126',
name: '王小虎',
amount1: '539',
amount2: '4.1',
amount3: 15
}, {
id: '12987126',
name: '王小虎3',
amount1: '539',
amount2: '4.1',
amount3: 15
}, {
id: '12987126',
name: '王小虎2',
amount1: '539',
amount2: '4.1',
amount3: 15
}, {
id: '12987126',
name: '王小虎2',
amount1: '539',
amount2: '4.1',
amount3: 15
}],
needMergeArr: ['name', 'id'], // 有合并項的列
rowMergeArrs: {}, // 包含需要一個或多個合并項信息的對象
};
},
methods:{
/**
* @description 實現合并行或列
* @param row:Object 需要合并的列name 如:'name' 'id'
* @param column:Object 當前行的行數,由合并函數傳入
* @param rowIndex:Number 當前列的數據,由合并函數傳入
* @param columnIndex:Number 當前列的數據,由合并函數傳入
*
* @return 函數可以返回一個包含兩個元素的數組,第一個元素代表rowspan,第二個元素代表colspan。 也可以返回一個鍵名為rowspan和colspan的對象
* 參考地址:https://element.eleme.cn/#/zh-CN/component/table#table-biao-ge
*/
arraySpanMethod({ row, column, rowIndex, columnIndex }) {
// 沒辦法循環判斷具體是那一列 所以就只好寫了多個if
if (column.property === 'name') return this.mergeAction('name', rowIndex, column);
if (column.property === 'id') return this.mergeAction('id', rowIndex, column);
},
/**
* @description 根據數組來確定單元格是否需要合并
* @param val:String 需要合并的列name 如:'name' 'id'
* @param rowIndex:Number 當前行的行數,由合并函數傳入
* @param colData:Object 當前列的數據,由合并函數傳入
*
* @return 返回值為一個數組表示該單元格是否需要合并; 說明: [0,0]表示改行被合并了 [n+,1]n為1時表示該單元格不動,n大于1時表示合并了N-1個單元格
*/
mergeAction(val, rowIndex, colData) {
let _row = this.rowMergeArrs[val].rowArr[rowIndex];
let _col = _row > 0 ? 1 : 0;
return [_row, _col];
},
/**
* @description 根據數組將指定對象轉化為相應的數組
* @param arr:Array[String] 必填 必須是字符串形式的數組
* @param data:Array 必填 需要轉化的對象
*
* @return 返回一個對象
* 例:rowMerge(['name','value'], [{value:'1', name:'小明'}, {value:'2', name:'小明'}, {value:'3', name:'小明'}, {value:'1', name:'小明'}, {value:'1', name:'小明'}])
* 返回值: {
* name:{
* rowArr: [5, 0, 0, 0, 0]
* rowMergeNum: 0,
* },
* value: {
* rowArr: [1, 1, 1, 2, 0],
* rowMergeNum: 3
* }
* }
*/
rowMergeHandle(arr, data) {
if (!Array.isArray(arr) && !arr.length) return false;
if (!Array.isArray(data) && !data.length) return false;
let needMerge = {};
arr.forEach(i => {
needMerge[i] = {
rowArr: [],
rowMergeNum: 0
};
data.forEach((item, index) => {
if (index === 0) {
needMerge[i].rowArr.push(1);
needMerge[i].rowMergeNum = 0;
} else {
if (item[i] === data[index - 1][i]) {
needMerge[i].rowArr[needMerge[i].rowMergeNum] += 1;
needMerge[i].rowArr.push(0);
} else {
needMerge[i].rowArr.push(1);
needMerge[i].rowMergeNum = index;
}
}
});
});
return needMerge;
}
}
},
mounted(){
this.rowMergeArrs = this.rowMergeHandle(this.needMergeArr, this.tableData); // 處理數據
}
}
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