You are a product manager and currently leading a team to develop a new product. Unfortunately, the latest version of your product fails the quality check. Since each version is developed based on the previous version, all the versions after a bad version are also bad.

Suppose you have n versions [1, 2, ..., n] and you want to find out the first bad one, which causes all the following ones to be bad.

You are given an API bool isBadVersion(version) which will return whether version is bad. Implement a function to find the first bad version. You should minimize the number of calls to the API.

從第i個版本開始的版本都是損壞的，題目隱藏的意思是有序連續，你可以吧good看成0；bad看成1，用二分就好了
···
/* The isBadVersion API is defined in the parent class VersionControl.
boolean isBadVersion(int version); */

public class Solution extends VersionControl {
public int firstBadVersion(int n) {
int lo = 1;
int hi = n;
while(lo<=hi)
{
int mid = lo+(hi-lo)/2;
if(isBadVersion(mid))
hi=mid-1;
else
lo=mid+1;
}
return lo;
}
}
···