題一:順時針轉圈打印矩陣
public void solve(int[][] matrix) {
int line = matrix.length;
int row = matrix[0].length;
//其實把for改成while看起來更干凈些,下面的print里也是
//PS:row 英語原意是行 column是列
int startLine = 0, startRow = 0, endLine = line-1, endRow = row-1;
for (; startLine <= endLine && startRow <= endRow; startLine++,startRow++,endLine--,endRow--) {
print(matrix, startLine, startRow, endLine, endRow);
}
}
/**
*
* @param matrix 矩陣
* @param startLine 左上角開始節點的行
* @param startRow 左上角開始節點的列
* @param endLine 右下角結束節點的行
* @param endRow 右下角結束節點的列
*/
private void print(int[][] matrix, int startLine, int startRow, int endLine, int endRow) {
int i;
if (startLine == endLine) {
for (i = startRow; i <= endRow; i++) {
System.out.print(matrix[startLine][i] + " ");
}
return;
}
if (startRow == endRow) {
for (i = startLine; i <= endLine; i++) {
System.out.print(matrix[i][startRow] + " ");
}
return;
}
for (i = startRow; i <= endRow; i++) {
System.out.print(matrix[startLine][i] + " ");
}
for (i = startLine + 1; i <= endLine; i++) {
System.out.print(matrix[i][endRow] + " ");
}
for(i = endRow-1; i >= startRow; i--) {
System.out.print(matrix[endLine][i] + " ");
}
for (i = endLine-1; i > startLine; i--) {
System.out.print(matrix[i][startRow] + " ");
}
}
public static void main(String[] args) {
Page331 instance = new Page331();
int[][] matrix = {{1,2,3,4}, {10,11,12,5}, {9,8,7,6}};
instance.solve(matrix);
System.out.println();
int[][] matrix2 = {{1,2,3},{8,9,4},{7,6,5}};
instance.solve(matrix2);
System.out.println();
int[][] matrix3 = {{1,2,3,4,5},{18,19,20,21,6},{17,28,29,22,7},{16,27,30,23,8},{15,26,25,24,9},{14,13,12,11,10}};
instance.solve(matrix3);
System.out.println();
int[][] matrix4 = {{1},{2},{3},{4}};
instance.solve(matrix4);
System.out.println();
int[][] matrix5 = {{1,2,3,4,5}};
instance.solve(matrix5);
}
題二:“之“字形打印矩陣
"之"字形打印矩陣
兩個指針:(sr,sc)先從第一行往右移動,到頭就往下;(er,ec)第一列往下,到頭往右
print方法里boolean控制打印方向,為true代表從下往上打印
注意 列比行長 與 行比列長 拐彎后不同的打印方向
public void solve(int[][] matrix) {
int rowL = matrix.length;
int columnL = matrix[0].length;
int sr = 0, sc = 0, er = 0, ec = 0;
while (sc < columnL && er < rowL) {
print(matrix, 0, sc, er, 0, (sc & 1) == 0);
sc++;
er++;
}
第一個指針沿著第一行到頭
if (sc == columnL && er < rowL) {
while (er < rowL) {
print(matrix, ++sr, columnL-1, er, 0, (er & 1) == 0);
er++;
}
此時er == rowL,也就是需要拐彎向右
while (sr < rowL-1) {
print(matrix, ++sr, columnL-1, rowL-1, ++ec, (sr & 1) == 0);
}
}
第二個指針沿著第一列到頭
else if (er == rowL && sc < columnL) {
while (sc < columnL) {
print(matrix, 0, sc, rowL-1, ++ec, (sc & 1) == 0);
sc++;
}
此時sc == columnL,需要拐彎向下
while (ec < columnL-1) {
print(matrix, ++sr, columnL-1, rowL-1, ++ec, (sr & 1) == 1);
}
}
方陣情況
else {
while (sr < rowL-1) {
print(matrix, ++sr, columnL-1, rowL-1, ++ec, (sr & 1) == 0);
}
}
}
orientation = true代表從下向上打印
private void print(int[][] matrix, int sr, int sc, int er, int ec, boolean orientation) {
if (orientation) {
while (er >= sr) {
System.out.print(matrix[er][ec] + " ");
er--;
ec++;
}
} else {
while (sr <= er) {
System.out.print(matrix[sr][sc] + " ");
sr++;
sc--;
}
}
}
public static void main(String[] args) {
Page335 instance = new Page335();
//列長
int[][] matrix = {{1,2,3,4}, {10,11,12,5}, {9,8,7,6}};
instance.solve(matrix);
//行長
System.out.println();
int[][] matrix3 = {{1,2,3,4,5},{18,19,20,21,6},{17,28,29,22,7},{16,27,30,23,8},{15,26,25,24,9},{14,13,12,11,10}};
instance.solve(matrix3);
System.out.println();
System.out.print("1 2 18 17 19 3 4 20 28 16 15 27 29 21 5 6 22 30 26 14 13 25 23 7 8 24 12 11 9 10" + "正確順序");
//方陣
System.out.println();
int[][] matrix2 = {{1,2,3},{8,9,4},{7,6,5}};
instance.solve(matrix2);
//單列
System.out.println();
int[][] matrix4 = {{1},{2},{3},{4}};
instance.solve(matrix4);
//單行
System.out.println();
int[][] matrix5 = {{1,2,3,4,5}};
instance.solve(matrix5);
System.out.println();
int[][] matrix6 = {{1,2,3,4,5},{6,7,8,9,10}};
instance.solve(matrix6);
System.out.println();
int[][] matrix7 = {{1,2},{3,4},{5,6},{7,8}};
instance.solve(matrix7);
}