需求：以。或者!或者？分割字符串
思路一：
NSString *testStr = @"我的世界觀。我的美女？我的老板！哈哈哈。";
NSString *pageStr = [self stringOfPage:index];??
? NSMutableArray*synthesisTexts = [NSMutableArrayarray];?
? NSArray*synthesisTemp = [testStr componentsSeparatedByString:@"。"];
在遍歷NSArray數(shù)組分別以？！分割
思路二：采用正則表達式分割
NSString *testStr = @"我的世界觀。我的美女？我的老板！哈哈哈。";
__block NSRange lastRange = NSMakeRange(-1, 0);
NSError *error = NULL;
NSRegularExpression *fieldRegularExpression = [NSRegularExpression
regularExpressionWithPattern:@"[。？！]"
options:NSRegularExpressionCaseInsensitive
error:&error];
[fieldRegularExpression enumerateMatchesInString:testStr options:0 range:NSMakeRange(0, [testStr length])
usingBlock:^(NSTextCheckingResult *match, NSMatchingFlags flags, BOOL *stop){
NSString *splitStr = [testStr substringWithRange:NSMakeRange(lastRange.location + 1, match.range.location - lastRange.location)];
NSLog(@"%@---%ld",splitStr,match.range.location+1);
lastRange = match.range;
}];
}
