Find the total area covered by two rectilinear rectangles in a 2D plane.

Each rectangle is defined by its bottom left corner and top right corner as shown in the figure.

Rectangle Area

Assume that the total area is never beyond the maximum possible value of int.

一刷
兩個矩形面積相加減去overlap

public class Solution {
    public int computeArea(int A, int B, int C, int D, int E, int F, int G, int H) {
        int areaOfSqrA = (C - A) * (D - B);//ABCD
        int areaOfSqrB = (G - E) * (H - F);//EFGH
        
        int left = Math.max(A, E);
        int right = Math.min(G, C);
        int bottom = Math.max(F, B);
        int top = Math.min(D, H);
        
        int overlap = 0;
        if(right>left && top>bottom){
            overlap = (right - left) * (top - bottom);
        }
        return areaOfSqrA + areaOfSqrB - overlap;
    }
}