Swift3更新后不兼容Swift2了,剛開始看Swift,發(fā)現(xiàn)好多方法都不能用了啊,那就只能自己摸索了,同時(shí)也在這與大家分享分享,正好讓大家?guī)臀抑刚?/p>
在這里更新到Swift4了歡迎大家查閱、、、
1.新建一個(gè)字符串,是不是很機(jī)智(懶)
let str = "Do any additional setup after loading the view, typically from a nib."
2.測(cè)量字符串長(zhǎng)度,因?yàn)镾wift的String保函uicode字符串,以前的length不好使了,然后百度了好多方法例如: countElements(string),然而,然并軟,并沒(méi)有用,是下面的方法,()是插值,以后再也不用OC的那一大串了。。。
print("string length: \(str.characters.count)")
3.獲取第一個(gè)到第十個(gè)字符
let index1 = str.index(str.startIndex, offsetBy: 10)
let str1 = str.substring(to: index1)
print("string from 1 - 10 : \(str1)")
//string from 1 - 10 : Do any add
4.獲取倒數(shù)十個(gè)字符
let index2 = str.index(str.endIndex, offsetBy: -10)
let str2 = str.substring(from: index2)
print("string of last 10 : \(str2)")
//string of last 10 : rom a nib.
5.獲取自定義范圍的字符串,比如4-6(any)
let index3 = str.index(str.startIndex, offsetBy: 3) //為啥是3...因?yàn)?..你懂得
let index4 = str.index(str.startIndex, offsetBy: 6)
let str3 = str.substring(with: index3..<index4)
print("string from 4 - 6 : \(str3)")
//string from 4 - 6 : any
6.獲取一個(gè)子字符串居然要那么長(zhǎng)的三行代碼?這怎么可以。。。立馬就想到了分類啦,但是Swift中沒(méi)有分類只有擴(kuò)展,但anyway功能是一樣的呀,我寫了個(gè)簡(jiǎn)單的,大家將就著用哈
import Foundation
extension String {
//獲取子字符串
func substingInRange(r: Range<Int>) -> String {
let startIndex = self.index(self.startIndex, offsetBy:r.lowerBound)
let endIndex = self.index(self.startIndex, offsetBy:r.upperBound)
return self.substring(with:startIndex..<endIndex)
}
}
嗯,下面是用法
let str4 = str.substingInRange(r: 3..<6)
print("string from 4 - 6 : \(str4)")
//string from 4 - 6 : any
7.其他很多方法都和OC類似,比如hasPrefix(),hasSuffix(),uppercaseString,lowercaseString之類的,就先寫到這里啦,在每天的下班后的有限的學(xué)習(xí)時(shí)間中發(fā)現(xiàn)了好玩的有時(shí)間就分享給大家,希望大家一起學(xué)習(xí)~
8.修改了下擴(kuò)展,加在這里
import Foundation
extension String {
//獲取子字符串
func substingInRange(r: Range<Int>) -> String? {
if r.lowerBound < 0 || r.upperBound > self.characters.count{
return nil
}
let startIndex = self.index(self.startIndex, offsetBy:r.lowerBound)
let endIndex = self.index(self.startIndex, offsetBy:r.upperBound)
return self.substring(with:startIndex..<endIndex)
}
}
//使用
if let str5 = str.substingInRange(r: 3..<6) {哦·
print("string from 4 - 6 : \(str5)")
} else {
print("range error")
}
//string from 4 - 6 : any
if let str6 = str.substingInRange(r: 3..<80) {
print("string from 4 - 80 : \(str6)")
} else {
print("range error")
}
//range erro