Find the contiguous subarray within an array (containing at least one number) which has the largest product.

For example, given the array [2,3,-2,4],
the contiguous subarray [2,3] has the largest product = 6.

分析：
本題要求連續(xù)子數(shù)組的最大乘積。需要考慮的是數(shù)組中存在0和負數(shù)的情況。具體代碼如下：

class Solution {
public:
    int maxProduct(vector<int>& nums) {
        int num = nums.size();
        int maxPro = nums[0], minPro = nums[0], ret = nums[0];
        
        for(int i = 1; i < num; ++i)
        {
            int a = maxPro*nums[i]; //若nuts[i] > 0,則a為最大值，反之a為最小值
            int b = minPro*nums[i];
            maxPro = max(max(a,b), nums[i]);  //考慮到nuts[i]== 0的情況，需要將nuts[i]進行比較，等到i+1是更新maxPro的值
            minPro = min(min(a,b), nums[i]);
            ret = max(maxPro,ret);//由于可能遇到中間有0的情況，因此每次都要更新最大值
        }
        
        return ret;
    }
};