1----數(shù)組----
1:數(shù)組簡(jiǎn)介
(1):OC中的數(shù)組能夠存放任意類型的數(shù)據(jù)AnyObject
(2):數(shù)組在內(nèi)存中存放是有序的，所以對(duì)一個(gè)集合中存放的數(shù)據(jù)進(jìn)行排序使用的就是數(shù)組
(3):不可變NSArray繼承與可變數(shù)組NSMutableArray
2:不可變數(shù)組方法
//1.數(shù)組的創(chuàng)建
let arr1: NSArray = NSArray.init(objects: 10,"hello",1.234)
print(arr1)
let arr2: NSArray = [1,2,3,4,5,7,8]
print(arr2)
//將數(shù)組所有內(nèi)容全部賦給另一數(shù)組 （表格、集合視圖中）
let arr3 = NSArray.init(array: arr2)
print(arr3)
let arr4 = NSArray.init(objects: arr3,100,"HELLO")
print(arr4)
print(arr4.count)
//2.遍歷數(shù)組
for i in 0..<arr4.count {
print(arr4[i])
}
for i in arr4 {
print(i)
}
//3.通過(guò)元素內(nèi)容 獲取對(duì)應(yīng)的索引
if arr4.containsObject(100) {
print(arr4.indexOfObject(100))
}
//4.獲取數(shù)組中第一個(gè)元素和最后一個(gè)元素
print(arr4.firstObject)
print(arr4.lastObject)
//5.將數(shù)組中的元素用指定的字符串進(jìn)行拼接
//拼接的結(jié)果是一個(gè)字符串
let arr_1: NSArray = ["中國(guó)","????","China",75]
let str_1 = arr_1.componentsJoinedByString("-")
print(str_1)
//6.將字符串按照指定的字符串進(jìn)行分割 --- 分割的結(jié)果是一個(gè)數(shù)組
var str_path: NSString = "http://www.baidu.com:1234/s?wd=ios&rsv_sug4=82&inputT=802"
var array: NSArray = str_path.componentsSeparatedByString("http://")
let lastStr: NSString = array.lastObject as! NSString
var lastArr: NSArray = lastStr.componentsSeparatedByString(":")
print(lastArr.firstObject!)
//7.isKindOfClass判斷某個(gè)元素是否屬于某個(gè)類
class Cat {
func wash() -> Void {
print("喵星人正在洗臉")
}
}
let tom = Cat.init()
var array_2: NSArray = [1,"hello",tom]
for i in array_2 {
if i.isKindOfClass(Cat) {
(i as! Cat).wash()
}
}
3.可變數(shù)組方法
//1.定義可變數(shù)組對(duì)象
var mutableArr1 = NSMutableArray.init(capacity: 0)
var mutableArr2 = NSMutableArray.init(array: [1,2,3,4,5,6,78])
var mutableArr3: NSMutableArray = [1,"hello","1611"]
//2.添加
//追加
mutableArr1.addObject("123")
mutableArr1.addObject([1,2,3,4,5,6,7,8,9])
mutableArr1.addObject("123")
print(mutableArr1)
//插入
mutableArr1.insertObject("QianFeng", atIndex: 0)
print(mutableArr1)
//3.刪除
mutableArr1.removeLastObject()
//刪除指定元素 如果存在多個(gè)就一起刪除
if mutableArr1.containsObject("123") {
mutableArr1.removeObject("123")
print(mutableArr1)
}
//刪除指定索引處的元素
//mutableArr1.removeObjectAtIndex(0)
//刪除一定范圍內(nèi)的元素
mutableArr1.removeObjectsInRange(NSRange.init(location: 0, length: 1))
mutableArr1.removeAllObjects()
//4.修改
mutableArr2.replaceObjectAtIndex(0, withObject: ["one","two","three"])
print(mutableArr2)
//5.交換數(shù)組中元素的顯示位置
mutableArr2.exchangeObjectAtIndex(0, withObjectAtIndex: 2)
print(mutableArr2)
2----字典------
1.字典簡(jiǎn)介
(1):OC中字典也是由多個(gè)鍵值對(duì)組成
(2):字典用于查找，key值是唯一的，不能重復(fù)
(3):字典在內(nèi)存中存放是無(wú)序的
(4):OC中字典分為兩種：可變字典NSMutableDictionary和不可變字典NSDictionary.可變字典是不可變字典的子類 所以可變字典能使用不可變字典的所有方法
(5):OC字典能存放任意類型的數(shù)據(jù) 通常鍵是字符串 值是任意類型
2.不可變字典方法
//1.創(chuàng)建字典
var dic1: NSDictionary = ["1":"one","2":"two","3":"three"]
var dic2 = NSDictionary.init(objects: [1,2,3,3], forKeys: ["one","two","three","four"])
var dic3 = NSDictionary.init(dictionary: dic1)
//2.字典的遍歷
for (key,_) in dic1 {
let keystr = key as! String
print(keystr,dic1[keystr]!)
}
//3.獲取字典中鍵值對(duì)個(gè)數(shù)
print(dic1.count)
//4.獲取字典的所有鍵和所有值
print(dic1.allKeys)
print(dic1.allValues)
//5.通過(guò)值獲取所有的鍵
print(dic2.allKeysForObject(3))
3:可變字典方法
let mutableDic1 = NSMutableDictionary.init(capacity: 0)
let mutableDic2 = NSMutableDictionary.init(dictionary: dic1)
//1.添加
mutableDic1.setObject("盜墓筆記", forKey: "movie")
mutableDic1.setObject("喬布斯傳", forKey: "book")
//字典或者數(shù)組中存在中文直接調(diào)用字典或者數(shù)組對(duì)象 中文是要以UTF8格式轉(zhuǎn)碼
func printDic(mutableDic1: NSMutableDictionary) {
for (key,_) in mutableDic1 {
let keystr = key as! String
print(keystr,mutableDic1[keystr]!)
}
}
//2.修改
mutableDic1.setObject("美人魚", forKey: "movie")
printDic(mutableDic1)
//3.刪除
mutableDic1.removeObjectForKey("movie")
printDic(mutableDic1)
mutableDic1.removeAllObjects()
printDic(mutableDic1)
