Optional and Default Parameters
- 如果默認參數被用作尾參數,那么它起的作用和尾參數是可選的作用是一樣的:
function buildName(firstName: string, lastName?: string) {
// ...
}
function buildName(firstName: string, lastName = "Smith") {
// ...
}
(firstName: string, lastName?: string) => string
- 可選參數如果有,那么只能放在尾參數
- 默認參數位置任意,其類型由默認值決定,也就是說如果賦值了,那么值只能是設定的默認值的類型或者
undefined
function buildName(firstName = "sss", lastName: string) {
return firstName + " " + lastName;
}
let result3 = buildName(undefined | string , "ssss");
console.log(result3);
Rest Parameters
-
...
用于無窮個可選參數,用于類型里面定義rest
參數
function buildName(firstName: string, ...restOfName: string[]) {
return firstName + " " + restOfName.join(" ");
}
let buildNameFun: (fname: string, ...rest: string[]) => string = buildName;
this
this是在函數調用時被設定的變量
let deck = {
suits: ["hearts", "spades", "clubs", "diamonds"],
cards: Array(52),
createCardPicker: function() {
return function() {
let pickedCard = Math.floor(Math.random() * 52);
let pickedSuit = Math.floor(pickedCard / 13);
return {suit: this.suits[pickedSuit], card: pickedCard % 13};
}
}
}
let cardPicker = deck.createCardPicker();
let pickedCard = cardPicker();
//出錯,this.suits[pickedSuit] this被綁定到了 window | undefined
alert("card: " + pickedCard.card + " of " + pickedCard.suit);
this
和arrow function
- 通過使用
arrow function
綁定函數的上下文 - 可以通過執行加上
--noImplicitThis
來幫助提醒可能存在的綁定上下文錯誤
let deck = {
suits: ["hearts", "spades", "clubs", "diamonds"],
cards: Array(52),
createCardPicker: function() {
// NOTE: the line below is now an arrow function, allowing us to capture 'this' right here
return () => {
let pickedCard = Math.floor(Math.random() * 52);
let pickedSuit = Math.floor(pickedCard / 13);
return {suit: this.suits[pickedSuit], card: pickedCard % 13};
}
}
}
let cardPicker = deck.createCardPicker();
let pickedCard = cardPicker();
alert("card: " + pickedCard.card + " of " + pickedCard.suit);
this parameter
- 然而,即使
arrow function
綁定了上下文,但是,this.suits[pickedSuit]的類型依然是any
,因為this
來源于對象字面量內部的函數表達式 - 所以TypeScript提供一個
this parameter
來修復這個bug
interface Card {
suit: string;
card: number;
}
interface Deck {
suits: string[];
cards: number[];
createCardPicker(this: Deck): () => Card;
}
let deck: Deck = {
suits: ["hearts", "spades", "clubs", "diamonds"],
cards: Array(52),
// NOTE: The function now explicitly specifies that its callee must be of type Deck
createCardPicker: function(this: Deck) {
return () => {
let pickedCard = Math.floor(Math.random() * 52);
let pickedSuit = Math.floor(pickedCard / 13);
return {suit: this.suits[pickedSuit], card: pickedCard % 13};
}
}
}
let cardPicker = deck.createCardPicker();
let pickedCard = cardPicker();
alert("card: " + pickedCard.card + " of " + pickedCard.suit);
這樣就修復了bug,TypeScript知道了this
的類型是Deck
,就沒有any
錯誤了
- this parameter in callbacks
當函數作為參數傳入一個一個庫中的函數中的時候,這些庫會把傳入的函數當做普通的函數處理,因此這個函數捕獲的this
會變成undefined
,所以在這個函數內涉及到this的會報錯。
通過以下幾步解決錯誤,而且可以使用this
- 首先通過
fake parameter this
,確保傳入的參數函數是不會捕獲this
,第一層檢查。
interface UIElement {
addClickListener(onclick: (this: void, e: Event) => void): void;
}
- 然后通過箭頭函數來幫忙
class Handler {
info: string;
onClickGood = (e: Event) => { this.info = e.message }
}
以上可以會有缺點。那就是每次傳建一個Handler類型的對象都會創建一個新的arrow function
,造成浪費,解決辦法是在Handler的原型上創建公用的方法
Overloads
JavaScript函數對于不同的參數可能返回不同類型的對象等等,所以需要如下措施來幫助做type-check
- 通過
overloads
和調用函數相同名字的函數組,來檢查每一個可能產生的結果。
let suits = ["hearts", "spades", "clubs", "diamonds"];
function pickCard(x: {suit: string; card: number; }[]): number;
function pickCard(x: number): {suit: string; card: number; };
function pickCard(x): any {
// Check to see if we're working with an object/array
// if so, they gave us the deck and we'll pick the card
if (typeof x == "object") {
let pickedCard = Math.floor(Math.random() * x.length);
return pickedCard;
}
// Otherwise just let them pick the card
else if (typeof x == "number") {
let pickedSuit = Math.floor(x / 13);
return { suit: suits[pickedSuit], card: x % 13 };
}
}
let myDeck = [{ suit: "diamonds", card: 2 }, { suit: "spades", card: 10 }, { suit: "hearts", card: 4 }];
let pickedCard1 = myDeck[pickCard(myDeck)];
alert("card: " + pickedCard1.card + " of " + pickedCard1.suit);
let pickedCard2 = pickCard(15);
alert("card: " + pickedCard2.card + " of " + pickedCard2.suit);