實訓總結20170916

CREATE TABLE city(

province_code INT,

province_name string,

city_code INT,

city_name string

)

ROW FORMAT delimited

fields terminated by ','

lines terminated by '\n';

load數據到hive表: load data local inpath '/home/bigdata//hive/city.txt' into table city;

查看創建表 show create table city;

查看表信息 desc city;

修改表:alter table city rename to city_name;

復制表: create table city like city_code;

刪除庫 drop database **;

刪除表 drop table **;

查表內容 select * from city limit 10;

顯示列名 set hive.cli.print.header=true;

建庫

建表

查詢相關命令? 最大的10個:select * from city order by city_code desc limit 10;

擁有最多市的省份:省里市的數目:取最多的10個省:

select province_name,count(city_name) as cnt from city group by province_name order by cnt desc limit 10;

去重統計 有多少個省:distinct

1)select count(distinct province_name) from city;

兩重:2)select count(1)

from

(

select province_name from city group by province_name

) a;

查出只有一個市的省份:省有多少市 ;市為1

1)

select

province_name, cnt

from

(

select province_name,count(1) as cnt

from city

group by province_name

)a

where cnt =1;

2) select province_name count(1) as cnt from city group by province_name having cnt = 1;

外表:

table前加關鍵字external

遠端要用的location'/user/hzw/city/city.txt'

create external table city_ex(

province_code int,

province_name string,

city_code int,

city_name string)

row format delimited

fields terminated by','

lines terminated by'\n'

location '/user/hzw/city/';

內表:

create table city_in(

province_code int,

province_name string,

city_code int,

city_name string)

row format delimited

fields terminated by','

lines terminated by'\n'

location '/user/hzw/city/';

2、使用分區patition對應表中的一個目錄;

靜態分區需要在sql語句中指定;

CREATE TABLE `user`(

`uid` INT,

`city_code` INT,

`model` string,

`access` string

)

row FORMAT delimited

fields terminated by ','

lines terminated by '\n';

load data local inpath '/home/bigdata/tanqi/hive/user.txt' into table user;

查詢user: select count(*) from user;

a.靜態分區:

create table user_daily(

uid int,

city_code int,

model string,

access string

)

partitioned by (p_data string);

插入數據從user :

insert overwrite table user_daily partition (p_data='2017-09-01')

select * from user;

b.動態分區

set hive.exec.dynamic.partition.mode=nonstrict;

insert overwrite table user_daily partition (p_data)

select *,'2017-09-02' from user

union all

select *,'2017-09-04' from user;

ALTER TABLE user_daily PARTITION (p_date='2017-01-01') RENAME TO PARTITION (p_date='20170101');

3.作業

a) 統計WIFI環境下用戶最多的5個城市

Select city_code,count(*) as cnt from user where access='WIFI'

group by city_code order by cnt desc limit 5;

b) 統計用戶數>=3的access和city_code組合

select access,city_code,count(*) as cnt from user

group by access,city_code

having cnt >=3 order by cnt desc;

c) 機型中帶有ne(不區分大小寫),不同access及對應用戶數

select access,count(*) as cnt from user

where lower(model) like '%ne%'

group by access order by cnt desc;

判斷 access里的名/總數的sum

select sum(if(access='WIFI',1,0))/count(1) from user;

select sum(if(access='2G',1,0))/count(1) from user;

select sum(if(access='4G',1,0))/count(1) from user;

if條件多

select

case

when uid % 10 in (0, 1, 2, 3) then '0-3'

when uid % 10 in (4, 5, 6, 7) then '4-7'

else '8-9'

end as interval,

count(*) as cnt

from user

group by

case

when uid % 10 in (0, 1, 2, 3) then '0-3'

when uid % 10 in (4, 5, 6, 7) then '4-7'

else '8-9'

end;

晚間

1、? list 集合

collect_set 去重的集合

collect_list 不去重

select collect_set(access) from user;

select collect_list(access) from user;

2、 hive 各種連接join

左連接 left outer join

右連接 right outer join

內連接 inner join? 找出左右相同(AB相交)的記錄

全連接 full join

select user.uid,user.city_code,city.city_name

from

(select * from user where uid <=100) user

left join

(select * from city where province_code <=30)city

on (user.city_code = city.city_code)

limit 20;

select user.uid,user.city_code,city.city_name

from

(select * from user where uid <=100) user

full join

(select * from city where province_code <=30)city

on (user.city_code = city.city_code)

limit 20;

3、分組top N

分組 access

排序 序號 city_code

top1 序號=1

select access,city_code,uid

from

(

select uid, access,city_code,

row_number() over (partition by access order

by city_code desc)as row_num

from user

)a

where row_num = 1;

4、累計? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? ? 第一行? ? ? ? ? ? ? 當前行

select p_date,

sum(cnt) over(order by p_date asc rows between unbounded preceding and current row)

from

(

select p_date, count(*) as cnt

from user_daily

where p_date between '2017-09-01' and '2017-09-30'

group by p_date

)a

;

最后編輯于
?著作權歸作者所有,轉載或內容合作請聯系作者
平臺聲明:文章內容(如有圖片或視頻亦包括在內)由作者上傳并發布,文章內容僅代表作者本人觀點,簡書系信息發布平臺,僅提供信息存儲服務。

推薦閱讀更多精彩內容